Introduction To Modern Planar Transmission Lines. Anand K. Verma. Читать онлайн. Newlib. NEWLIB.NET

Автор: Anand K. Verma
Издательство: John Wiley & Sons Limited
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Жанр произведения: Техническая литература
Год издания: 0
isbn: 9781119632474
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input/output relations of the E‐field in both coordinate systems are expressed in terms of their respective Jones matrices:

      In the above expression, subscript “Car.” with Jones matric stands for the (y‐z) Cartesian coordinate system; and the subscript “e” with Jones matric stands for the general (e1‐e2) coordinate system. In the present case, it is the anticlockwise rotated Cartesian system, as shown in Fig. (4.12).

      (4.6.19)equation

      (4.6.20)equation

      On comparing the above equations against equation (4.6.18b), we get the transformed Jones matrix [J]e of the rotated polarizer in the (e1‐e2) coordinate system from the Jones matrix [J]Car of the original polarizer in the Cartesian (y‐z) coordinate system:

      The use of the coordinate transformation for the polarizer is illustrated below by a few illustrative simple examples. Application of Jones matrix to the more complex polarizing system is available in the reference [B.30].

       Examples:The Jones matrix of a linear polarizer given by equation (4.6.15c) is transformed below to the rotated Jones matrix [J]e = [JLP(θ)] of a linear polarizer that is rotated at an angle θ:(4.6.22) It is noted that the original linear polarizer in the Cartesian system has no cross‐polarization element. However, the rotated linear polarizer has a cross‐polarization element. The above transformation can be applied to the horizontal polarizer (py = 1, pz = 0) rotated at an angle θ, and also to the linear polarizer rotated at an angle θ = 45°, to get the following rotated Jones matrices:(4.6.23) The anisotropic polarizer with cross‐coupling, in the Cartesian system, is given by equation (4.6.14). The polarizer is rotated by an angle θ. The rotated Jones matrix of the anisotropic polarizer is obtained as follows:(4.6.24)

      Jones Matrix for Retarder (Phase Shifter)

      Jones Matrix of Half‐waveplate

      The Jones matrix of a half‐waveplate and the field components at its output are obtained by taking the relative phase Δφ = π:

      (4.6.26)equation

      It is noted that at the output of the half‐wave plate the phase difference between two field components is 180°. Two field components are in‐phase at the input of the half‐waveplate.

      Jones Matrix of Quarter‐waveplate

      The Jones matrix of a quarter‐wave retarder and also the field components at the output are obtained by taking the relative phase Δφ = − π/2:

      (4.6.27)equation

      In the above equation, both field components are equal to E0 = 1. It is noted that at the output of the quarter‐waveplate, the wave is a right‐hand circularly polarized wave. In the case, input wave components are images and images, the field components at the output of the quarter‐waveplate, using equation (4.6.25a) are