Introduction To Modern Planar Transmission Lines. Anand K. Verma. Читать онлайн. Newlib. NEWLIB.NET

Автор: Anand K. Verma
Издательство: John Wiley & Sons Limited
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Жанр произведения: Техническая литература
Год издания: 0
isbn: 9781119632474
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components. The tip of the electric vector (images) moves along line A‐O‐B with respect to time. However, the slant angle θ does not change with time. If both the E‐field components are either in‐phase (A − O − B) or out of phase (A/ − O − B/) and have the same magnitude, i.e. E0y = E0z = E0, the corresponding inclination angle of the linear polarization trace, with respect to the y‐axis, is θ = 45° and 135°, respectively. For the linear polarization, the total E‐field given by equation (4.6.1a) could also be written as follows:

      (4.6.3)equation

      

      4.6.2 Circular Polarization

      The circular polarization, shown in Fig. (4.10b), is obtained for two orthogonal field components of equal magnitude, and phase in quadrature. So, to get the circular polarization, two electric field components oscillate at the same frequency and meet the following conditions:

       Equal amplitude: The magnitudes of Ey and Ez are equal, i.e. |E0y| = |E0z| = E0.

       Space quadrature: The Ey and Ez field components are normal to each other.

       Time (phase) quadrature: The phase difference between the Ey and Ez field components are (φ = ± 90°), i.e. E0y = E0, and E0z = E0e±π/2 = ± j E0.

      The phasor form of the E‐field vector of the circularly polarized waves, meeting the above conditions, could be written from equation (4.6.1a) as follows:

      The ejωt time‐harmonic factor is suppressed in the above equations. The time‐domain forms of the circularly polarized waves, using the instantaneous images‐field components, at any location in the positive x‐direction and also at the x = 0, i.e. in the (y‐z)‐plane, are expressed as follows:

      (4.6.6)equation

      4.6.3 Elliptical Polarization

      Two orthogonal field components, in the space quadrature, of unequal magnitude and arbitrary phase angle (φ) between them, generate the elliptical polarization, i.e. the resultant E‐field vector rotates in the plane of polarization such that its tip traces an elliptical path as shown in Fig. (4.10c). The instantaneous orthogonal E‐field components in the x = 0 plane are given below:

      (4.6.7)equation

      Using the above equation and identity images the following equation of the ellipse is obtained:

      (4.6.8)equation

      The semi‐major axis OA, the semi‐minor axis OB of the ellipse shown in Fig. (4.10c), and the axial ratio (AR) of the polarization ellipse are given below [B.9, B.29]:

      The tilt angle θ of the polarization ellipse, i.e. inclination of the major axis OA with y‐axis is [B.9, B.29]:

      (4.6.10)equation

      

      4.6.4 Jones Matrix Description of Polarization States

      The polarizing devices change the state of polarization. For instance, the polarizing devices could change the rotation of the linear