It can be shown that the ΔF0 of reaction (3.103), needed for the estimation of
Table II. Kinetic and thermodynamic data for O2 + QH− reaction at 30∘Ca
aAll free energy units are in kcal mole−1. bThere is an appreciable uncertainty in
where
Note that M. is using here Latimer’s standard oxidation potentials whose values are opposite of IUPAC’s standard reduction potentials [73].
“F is the Faraday, and KS is the equilibrium constant of reaction (3.100) for the formation of semiquinones or indophenols. The ΔF0’s of Table II were estimated using the known [74]
Introducing into Eq. (3.4), these ΔF0’s and the effective radii later deduced, the
3.32.Excess Entropy of Activation
In this section, M. shows how it is possible to estimate unknown entropy values.
“All the entropy data needed for the estimation of
For example, just as in the case of the ferric-hydroquinone reaction, ΔS*expt can be calculated from the frequency factor of the pseudo-rate constant and the entropy of ionization of QH2, S1.
Assuming that S1 equals the value for the hydroquinones and water (which are later shown to be equal) one finds in this way that
The term
“Accordingly, if the entropy change S0 of reaction (3.103) were appreciable, the main contributions to it would arise from possible differences in the entropy of solvation of QH− and O−2. This would not be expected to be large so that S0/2 should be relatively small. Further, ΔF0/λ is calculated to be about 0.3, so we conclude that
3.33.Discussion
“A comparison of Tables I and II shows that the rate constants of the redox step in the two series of reactions considered here differ from each other by a factor 109 on the average. This difference stems from the considerable difference in the standard free energy change ΔF0 of the redox step in the two cases, one being about—13kcal mole−1, the other perhaps lying between +17 and + 12kcal mole−1, depending on the correct value of
According to the theory developed in Part I, the standard free energy change affects the reaction rate in the following way. During an ET step, there is first a reorganization of the solvent molecules about the reacting ions prior to the jump of an electron from one reactant to the other. Now, for a given