Molecular Imaging. Markus Rudin. Читать онлайн. Newlib. NEWLIB.NET

Автор: Markus Rudin
Издательство: Ingram
Серия:
Жанр произведения: Медицина
Год издания: 0
isbn: 9781786346865
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rel="nofollow" href="#fb3_img_img_72666e19-075e-5053-a420-878b682e7148.png" alt="image"/> As in the preceding reaction series discussed in Ref. [2], the rate constant k for the forward reaction in Eq. (3.103) can be inferred from the overall bimolecular rate constant k1 and the first ionization constant K1 of QH2 (k = k1[H+]/K1). The k’s and the values of image calculated from them using Eq. (3.1) are given in Table II.

      It can be shown that the ΔF0 of reaction (3.103), needed for the estimation of image is given by Eq. (3.104):

image image

      where image is the standard oxidation potential of QH2 (QH2 = Q + 2H+ + 2e), image is that of image

      Note that M. is using here Latimer’s standard oxidation potentials whose values are opposite of IUPAC’s standard reduction potentials [73].

      Introducing into Eq. (3.4), these ΔF0’s and the effective radii later deduced, the image values of Table II were computed.

       3.32.Excess Entropy of Activation

      In this section, M. shows how it is possible to estimate unknown entropy values.

      “All the entropy data needed for the estimation of image and image the experimental and the calculated excess entropy of activation of the electron transfer step, Eq. (3.103), are not available. However, some estimate of the undetermined entropy values may be made.

      For example, just as in the case of the ferric-hydroquinone reaction, ΔS*expt can be calculated from the frequency factor of the pseudo-rate constant and the entropy of ionization of QH2, S1.

      Assuming that S1 equals the value for the hydroquinones and water (which are later shown to be equal) one finds in this way that image cal mole−1 deg−1.

      The term image is seen from the approximate equation, Eq. (3.10), to be about S0(1 + ΔF0/λ)/2 since e1e2 and image are each equal to zero in reaction (3.103). In reaction (3.103), it is also expected that the translational, vibrational, and rotational entropies of the reactants are each about equal to those of the products.” Because of the very similar chemical structure of reagents and products.

      “Accordingly, if the entropy change S0 of reaction (3.103) were appreciable, the main contributions to it would arise from possible differences in the entropy of solvation of QH and O2. This would not be expected to be large so that S0/2 should be relatively small. Further, ΔF0/λ is calculated to be about 0.3, so we conclude that image is small, in agreement with the estimated small value of image

       3.33.Discussion

      “A comparison of Tables I and II shows that the rate constants of the redox step in the two series of reactions considered here differ from each other by a factor 109 on the average. This difference stems from the considerable difference in the standard free energy change ΔF0 of the redox step in the two cases, one being about—13kcal mole−1, the other perhaps lying between +17 and + 12kcal mole−1, depending on the correct value of image This difference in turn is related principally to the differences between standard oxidation potentials of the ferrous ion and of the oxygen molecule ion.

      According to the theory developed in Part I, the standard free energy change affects the reaction rate in the following way. During an ET step, there is first a reorganization of the solvent molecules about the reacting ions prior to the jump of an electron from one reactant to the other. Now, for a given