Molecular Imaging. Markus Rudin. Читать онлайн. Newlib. NEWLIB.NET

Автор: Markus Rudin
Издательство: Ingram
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Жанр произведения: Медицина
Год издания: 0
isbn: 9781786346865
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for the cited polyatomic ions would be approximately the actual crystallographic radii. This is also consistent with the assumption that only the first layer of the water molecules about a monoatomic ion is saturated, since a hydrated monoatomic ion has about the same radius as these polyatomic ions.

      With a slightly different for an ion when it is a reactant and when it is a product it was suggested that a mean value for a be adopted.” “The crystallographic radii of Fe+2, Fe+3, and H2O are [2] 0.75, 0.60, and 0.72. The mean of the first two is 0.68Å.”

      The refinements of the theory will take into account the effect of the radii variations on the reaction rate.

      When organic ions are considered one has to consider two new features. “First, the ion is far from being spherical and, second, it is possible that that the effective radius a could be quite different when this particle is a charged reactant and when it is an uncharged product. This is discussed later, where it is inferred from entropy data that the effective polarizing radius of a hydroquinone-like ion such as HOC6H4O is about the same as that of the hydroxyl ion. It is further suggested that the dielectric saturation around this group when it is a charged particle be neglected as a first approximation, and that a equals the crystallographic radius of the oxygen group 1.4Å. This approximation can be removed by a refinement of the theory.”

       3.29.Excess Free Energy of Activation

      “Experimental values of ΔF* were calculated from the rate constant k given in Table 1, using Eq. (3.1) and setting Z equal to 1013 liter mole−1 sec−1 in that equation. These values are reported in Table I.

      Using the effective radii and the ΔF0’s deduced in the preceding section and setting Dop = 1.8 and Ds = 78.5 at 25C, values of image were obtained with the aid of Eqs. (3.2)–(3.4), and are given in Table I. These results will be discussed in detail later.”

       3.30.Excess Entropy of Activation

      “Experimental values for the excess entropy of activation of reaction (3.99), image were calculated from the data.”

      It may be instructive to report, from note 26 in Ref. [2], how this calculation was done.

      The pseudo-rate constant k1 of Eq. (3.97) has an activation energy E1, say, and a frequency factor A1 so that k1 = A1 exp(−E1/RT). Values of A1 were determined experimentally. The rate constant k, Eq. (3.99), has a frequency factor A, say, which can be calculated from the known A1 [51] and the known [70] entropy of ionization of QH2, ΔS1 say. It is found that A = A1[H+] exp(− S1/R). According to Eq. (3.7), image is then found by setting A = Z exp(ΔS*/R), Z being in Ref. [2] equal to 1013 liter mole−1 sec−1 [72]. But see the previous note on the correct value of Z.

      “The values of image were computed from Eq. (3.9) using the previously determined radii and ΔF0 and using the calculated ΔS0.” From note 27 in Ref. [2]: “ΔS0 = − ΔF0/∂T and therefore according to Eq. (3.101), image where ΔS and ΔSS are the standard entropy changes in reactions (3.97) and (3.100), respectively [51, 70]. Since the sum of the translational, rotational, and vibrational entropies of the reactants and of the products of reaction should be about the same, it may be assumed that SS is essentially zero.”

      “In this way image was found to be 46, 57, 47, and 44cal mole−1 deg−1, and image to be 36, 38, 36, and 31 entropy units, for the 2,6-dichloro, benzo, tolu, and duro hydroquinones, respectively. The average of the former group of values is 49 and that of the latter is 35. Values of image were also computed from the approximate equation, Eq. (3.10). They agreed well with the exact calculated values, within about one and a half entropy units.”

       (b)AEROBIC OXIDATION OF THE LEUCOINDOPHENOLS

       3.31.Excess Free Energy of Activation

      “The overall reaction of the leucoindophenols with dissolved oxygen is represented by Eq. (3.102), where QH2 denotes a leucoindophenol such as HOC6H6NHC6H6OH, and Q denotes the corresponding indophenol HOC6H4NC6H4O.

      A mechanism consistent with the data [51] involved the ionization of QH2 to QH, which then transferred an electron to O2:

      This