There is an infinite number of pairs of intermediate states X∗ and X which could satisfy the free energy restriction (2.24). All of the pairs have the same charge distribution but the r-dependent Pu(r) is different for different pairs. The problem is now of determining the Pu(r) of that pair of “groups of atomic configurations” that “contribute to the macroscopic or ‘thermodynamic’ properties of the transition state TS” [19]. Such a pair, subject to the free energy restriction (2.24), is characterized by the minimum free energy F∗, because we are looking for that thermodynamic state which has the maximal probability of formation from the reactants.(7) In terms of atomic configurations, one can say that many of them can satisfy the energy restriction, but only a group of atomic configurations contribute to the macroscopic or “thermodynamic” properties of the TS, namely those which minimize its free energy of formation from the reactants [19]. I give here the final results for Pu and F∗. They allow the calculation of ΔF∗, which is one of the major results of the Marcus theory.
The work
Similarly for
Marcus obtained for the Pu(r) and the F∗:
Using the preceding results Marcus obtained the famous formula for ΔF∗:
where we have used the conservation of charge relation
In order to properly appreciate the earlier astonishing final result, the reader should consider that it was obtained by three very clever steps. In the first one, M. discovered the beautiful general formulas (2.13) and (2.14) (appearing in the demonstration earlier in the form of Eq. (2.22)) for the electrostatic free energies F∗ and F. He then devised the minimization procedure to get the formulas for the free energies of the activated complexes. Finally, starting from an expression for F∗ depending on E∗, Pu, and Ec he ended up—as if by magic—with a formula of great simplicity and elegance and of immediate applicability depending on the charges
Let us use it to calculate the value of m for the electron exchange reaction:
We see that for this case each term on the RHS of Eq. (2.28) is zero. On the LHS, the terms in parenthesis are different from zero, Δe = 1 and so Eq. (2.28) can only be satisfied if 2m + 1 = 0, that is, if
To understand what this means, let us consider again formula (2.26) for the Pu which minimizes F∗.
We see that if
that is, the value of Pu which minimizes F∗ is the one that would be in equilibrium with a hypothetical electric field equal to the arithmetic average of the fields E∗ and E. And is consistent with the intuitive idea that the Pu of the TS would be in equilibrium with fictitious charges on the ions which would be averages between initial and final charges!
∗ Proof of Eqs. (2.26), (2.27), and (2.28)
At the minimum of F∗, we shall have δF∗ = 0 (M. uses here the Calculus of Variations, elements of which can be found in books of Advanced Calculus or of Mathematical Methods of Physics and Chemistry, for example in Refs. [20–24] and, more extensively, in Ref. [25]).
M. expresses the variation δF∗ as function of the variations δPu of the function Pu.
The charges are fixed, so
We have seen that
δF∗ depends on the variations of Pu and E∗. But we know that Pu