Molecular Imaging. Markus Rudin. Читать онлайн. Newlib. NEWLIB.NET

Автор: Markus Rudin
Издательство: Ingram
Серия:
Жанр произведения: Медицина
Год издания: 0
isbn: 9781786346865
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for ΔF

      The work image required to charge up two conducting spheres of charges image and image and of radii a1 and a2 in the dielectric medium is given by(8):

      Similarly for image

image

      Marcus obtained for the Pu(r) and the F:

      Using the preceding results Marcus obtained the famous formula for ΔF:

      where we have used the conservation of charge relation image image and R is the mean activation distance in the activated complex.

      In order to properly appreciate the earlier astonishing final result, the reader should consider that it was obtained by three very clever steps. In the first one, M. discovered the beautiful general formulas (2.13) and (2.14) (appearing in the demonstration earlier in the form of Eq. (2.22)) for the electrostatic free energies F and F. He then devised the minimization procedure to get the formulas for the free energies of the activated complexes. Finally, starting from an expression for F depending on E, Pu, and Ec he ended up—as if by magic—with a formula of great simplicity and elegance and of immediate applicability depending on the charges image the geometry of the system, (a1, a2, R), the dielectric properties of the medium (Dop and Ds), and the thermodynamic quantities ΔF0 and T ΔSe which appear through the Lagrangian multiplier m obtained from the formula:

      Let us use it to calculate the value of m for the electron exchange reaction:

image

      We see that for this case each term on the RHS of Eq. (2.28) is zero. On the LHS, the terms in parenthesis are different from zero, Δe = 1 and so Eq. (2.28) can only be satisfied if 2m + 1 = 0, that is, if image

      To understand what this means, let us consider again formula (2.26) for the Pu which minimizes F.

      We see that if image

image

      that is, the value of Pu which minimizes F is the one that would be in equilibrium with a hypothetical electric field equal to the arithmetic average of the fields E and E. And is consistent with the intuitive idea that the Pu of the TS would be in equilibrium with fictitious charges on the ions which would be averages between initial and final charges!

       Proof of Eqs. (2.26), (2.27), and (2.28)

      M. expresses the variation δF as function of the variations δPu of the function Pu.

      The charges are fixed, so image is fixed and image Computing δF from Eq. (2.13) one obtains:

image

      We have seen that image so that:

      δF depends on the variations of Pu and E. But we know that Pu