Population Genetics. Matthew B. Hamilton. Читать онлайн. Newlib. NEWLIB.NET

Автор: Matthew B. Hamilton
Издательство: John Wiley & Sons Limited
Серия:
Жанр произведения: Биология
Год издания: 0
isbn: 9781118436899
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two alleles each:

equation

      For the hypothesis of one locus with three alleles:

equation

      The expected numbers of each genotype as well as the differences between the observed and expected genotype frequencies are worked out in the tables. For the hypothesis of two loci with two alleles each, χ2 = 0.266, whereas χ2 = 19 688 for the hypothesis of one locus with three alleles. Both of these tests have one degree of freedom (4 genotypes −2 for estimated allele frequencies −1 for the test), giving a critical value of χ20.05,1 = 3.84 from Table 2.5. The deviations between observed and expected genotype frequencies could easily be due to chance under the hypothesis of two loci with two alleles each. However, the observed genotype frequencies are extremely unlikely under the hypothesis of three alleles at one locus since the deviations between observed and expected genotype frequencies are very large.

Phenotype Genotype Observed Expected number of genotypes Observed − expected (Observed − expected)2/expected
Hypothesis 1: two loci with two alleles each
Purple/smooth A_B_ 2058 3816 (1–0.522)(1–0.512) = 2060.0 2.0 0.002
Purple/wrinkled A_bb 728 3816 (1–0.522)(0.51)2 = 724.2 3.8 0.020
Yellow/smooth aaB_ 769 3816 (0.52)2(1–0.512) = 763.5 5.5 0.040
Yellow/wrinkled Aabb 261 3816 (0.52)2(0.51)2 = 268.4 −7.4 0.204
Hypothesis 2: one locus with three alleles
Purple/smooth AB 2058 3816 (2(0.48)(0.49)) = 1795 63.0 38.5
Purple/wrinkled AA, AC 728 3816 ((0.48)2 + 2(0.48)(0.03)) = 989.1 −261.1 68.9
Yellow/smooth BB, BC 769 3816 ((0.49)2 + 2(0.49)(0.03)) = 1028.4 − 259.4 63.7
Yellow/wrinkled CC 261 3816 (0.03)2 = 3.4 257.6 19 517.0

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