Vibroacoustic Simulation. Alexander Peiffer. Читать онлайн. Newlib. NEWLIB.NET

Автор: Alexander Peiffer
Издательство: John Wiley & Sons Limited
Серия:
Жанр произведения: Отраслевые издания
Год издания: 0
isbn: 9781119849865
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Baseline Over upper T EndFraction d upper T 2nd Column plus 3rd Column StartFraction upper P Over upper T EndFraction d left-parenthesis StartFraction 1 Over rho EndFraction right-parenthesis 4th Row 1st Column equals StartFraction c Subscript normal v Baseline Over upper T EndFraction d upper T 2nd Column plus 3rd Column StartFraction upper P Over upper T rho squared EndFraction d rho EndLayout"/> (2.10)

      The relation dv=d(1/ρ) comes from the fact that v is a mass specific value and therefore the reciprocal of the density ρ=1/v. For an ideal gas we have

      cp and cv are the specific thermal heat capacities for constant pressure and volume, respectively. That is the ratio of temperature change ∂T per increase of heat ∂q. From the total differential

      we can derive

       StartFraction d upper T Over upper T EndFraction equals StartFraction d upper P Over upper P EndFraction minus StartFraction d rho Over rho EndFraction (2.13)

      Using all above relations the change in density dρ is:

       d rho equals StartFraction rho Over kappa upper P EndFraction d upper P minus StartFraction rho Over c Subscript normal p Baseline EndFraction d s (2.14)

      with κ=cv/cp. In most acoustic cases the process is isotropic: i.e. time scales are too short for heat exchange in a free gas; thus ds=0, and the change of pressure per density is

      In case of constant temperature (isothermal) dT=0 we get with (2.12) and the ideal gas law (2.11):

       upper K equals rho left-parenthesis StartFraction partial-differential upper P Over partial-differential rho EndFraction right-parenthesis (2.17)

      Due to (2.15) and (2.16) the relationship between the bulk modulus K and c0 is:

       c 0 squared equals StartFraction upper K Over rho EndFraction (2.18)

      The bulk modulus can be defined for gases too, but we must distinguish between isothermal or adiabatic processes.

       StartLayout 1st Row 1st Column upper K Subscript normal s 2nd Column rho left-parenthesis StartFraction partial-differential upper P Over partial-differential rho EndFraction right-parenthesis Subscript normal s Baseline equals kappa upper P 3rd Column upper K Subscript upper T 4th Column rho left-parenthesis StartFraction partial-differential upper P Over partial-differential rho EndFraction right-parenthesis Subscript upper T Baseline equals upper P EndLayout (2.19)

      2.2.4 Linearized Equations

      Equations (2.3) and (2.8) can be linearized if small changes around a certain equilibrium are considered:

       StartLayout 1st Row 1st Column upper P 2nd Column equals 3rd Column upper P 0 plus p EndLayout (2.21)

      Inserting (2.22) into the equation of continuity (2.3), neglecting all second order terms as far as source terms, and setting1 v0=0 the linear equation of continuity is:

      Doing the same for the equation of motion (2.8) leads to:

      Using the curl(∇×) of this equation it can be shown that the acoustic velocity v′ can be expressed using a so-called velocity potential which will be useful for the calculation of some wave propagation phenomena.

      From the following operation

StartFraction partial-differential Over partial-differential t EndFraction left-parenthesis 2.23 right-parenthesis minus nabla left-parenthesis 2.24 right-parenthesis

      follows

       StartFraction partial-differential squared rho prime Over partial-differential t squared EndFraction minus nabla squared p equals 0 (2.26)

      With the equation of state (2.15) for the density we get the linear wave equation for the acoustic pressure p