Probability. Robert P. Dobrow. Читать онлайн. Newlib. NEWLIB.NET

Автор: Robert P. Dobrow
Издательство: John Wiley & Sons Limited
Серия:
Жанр произведения: Математика
Год издания: 0
isbn: 9781119692416
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0 comma 0 comma 0 right-parenthesis"/>.

      Conversely, given a list of zeros and ones, we select those people corresponding to the ones in the list. That is, if a one is in the kth position in the list, then person k is selected. If the list is left-parenthesis 1 comma 0 comma 1 comma 1 comma 1 comma 1 right-parenthesis, then all but the second person are selected.

      A one-to-one correspondence between two finite sets means that both sets have the same number of elements. Our one-to-one correspondence shows that the number of subsets of an n-element set is equal to the number of binary lists of length n. The number of binary lists of length n is easily counted by the multiplication principle. As there are two choices for each element of the list, there are 2 Superscript n binary lists. The number of subsets of an n-element set immediately follows as 2 Superscript n.

Subset List
empty-set left-parenthesis 0 comma 0 comma 0 right-parenthesis
StartSet 1 EndSet left-parenthesis 1 comma 0 comma 0 right-parenthesis
StartSet 2 EndSet left-parenthesis 0 comma 1 comma 0 right-parenthesis
StartSet 3 EndSet left-parenthesis 0 comma 0 comma 1 right-parenthesis
StartSet 1 comma 2 EndSet left-parenthesis 1 comma 1 comma 0 right-parenthesis
StartSet 1 comma 3 EndSet left-parenthesis 1 comma 0 comma 1 right-parenthesis
StartSet 2 comma 3 EndSet left-parenthesis 0 comma 1 comma 1 right-parenthesis
StartSet 1 comma 2 comma 3 EndSet left-parenthesis 1 comma 1 comma 1 right-parenthesis

      1.7.1 Combinations and Binomial Coefficients

StartSet 1 comma 2 EndSet comma StartSet 1 comma 3 EndSet comma StartSet 1 comma 4 EndSet comma StartSet 2 comma 3 EndSet comma StartSet 2 comma 4 EndSet comma StartSet 3 comma 4 EndSet

      with corresponding lists

left-parenthesis 1 comma 1 comma 0 comma 0 right-parenthesis comma left-parenthesis 1 comma 0 comma 1 comma 0 right-parenthesis comma left-parenthesis 1 comma 0 comma 0 comma 1 right-parenthesis comma left-parenthesis 0 comma 1 comma 1 comma 0 right-parenthesis comma left-parenthesis 0 comma 1 comma 0 comma 1 right-parenthesis comma left-parenthesis 0 comma 0 comma 1 comma 1 right-parenthesis period

      Given a specific k-element subset, there are k factorial ordered lists that can be formed