(2.2.9)
(2.2.10)
Finally, the voltage distribution on the nth line section and the voltage at the nth line junction can be written as follows:
(2.2.11)
(2.2.12)
2.2.2 Location of Sources
The shunt voltage
Current Source at the Junction of Finite Length Line and Infinite Length Line
Figure (2.11a) shows a transmission line circuit with a current source IS located at x = 0 that is the junction of two lines of different electrical characteristics. The open‐circuited line #1, with length x = −d1, is located at the left‐hand side of the current source. Its characteristics impedance/admittance is (Z01/Y01) and its propagation constant is β1. The infinite length line #2, with characteristics impedance/admittance (Z02/Y02) and the propagation constant β2, is located at the right‐hand side of the current source. It can be replaced by a load admittance YL = Y02 at a distance x = d2, shown in Fig (2.11b). The objective is to find out the voltage waves on both the lines as excited by the current source.
Figure 2.11 A shunt current source at the junction of two‐line sections.
The current source IS can be replaced by an equivalent voltage source Vs, shown in Fig (2.11c), at x = 0:
(2.2.13)
where Yin is the total load admittance at the plane containing the current source IS. Y− and Y+ are left‐hand and right‐hand side admittances at x = 0 given by
(2.2.14)
The general solution of a voltage wave is given by equation (2.1.79a). The constants V+ and V− are evaluated for the left‐hand side of a lossless transmission line. At x = 0, V(x = 0) = Vs. On using this boundary condition in equation (2.1.79a): VS = V+ + V−. At x = −d1 the line is open‐circuited with I (x = −d1) = 0. On using this boundary condition in equation (2.1.79b):
The voltage wave on the left‐hand line #1 is obtained by substituting equation (2.2.15) in equation (2.1.79a):
The line at the right‐hand side of the current source is an infinite length line that supports a traveling wave without any reflection. Therefore, at x = 0, V− = 0 and V+ = VS. The voltage wave on line #2 at the right‐hand side is
(2.2.17)
The method can be easily extended to a multisection line structure. For this purpose, the left‐hand and right‐hand side admittances Y− and Y+ are determined at the plane containing the current source.
Series Voltage Source
Figure (2.12a) shows the series‐connected voltage source VS at x = 0. The location x = 0 is a junction of two transmission lines – line #1 open‐circuited finite‐length line and line #2 infinite length line. The lines at the left‐hand and right‐hand sides of the voltage source can be replaced by the equivalent impedances Z− and Z+, respectively. It is shown in the equivalent circuit, Fig (2.12b). Again, the voltage waves on both lines, excited by a series voltage source, could be determined.
The voltages across loads Z− (Z1) and Z+ (Z2), shown in Fig (2.12b), are obtained as follows:
Line #1 is open‐circuited and line #2 is of infinite extent. Therefore, their input impedances at x = 0− and x = 0+ are
Figure 2.12 A series voltage source at the junction of two‐line sections.
The voltage at x = 0+ from equations (2.2.18c) and (2.2.19) is
(2.2.20)
For a lossy transmission line, the above equation could be written as follows:
(2.1.21)