Wind Energy Handbook. Michael Barton Graham. Читать онлайн. Newlib. NEWLIB.NET

Автор: Michael Barton Graham
Издательство: John Wiley & Sons Limited
Серия:
Жанр произведения: Физика
Год издания: 0
isbn: 9781119451167
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W squared italic upper B c left-parenthesis upper C Subscript l Baseline cosine phi plus upper C Subscript d Baseline sine phi right-parenthesis delta r"/>

      The torque on an annular ring is

      where B is the number of blades.

      The basic assumption of the BEM theory is that the force of a blade element is solely responsible for the change of axial momentum of the air that passes through the annulus swept by the element. It is therefore to be assumed that there is no radial interaction between the flows through contiguous annuli: a condition that is, strictly, only true if pressure gradients acting axially on the curved streamlines can be neglected if the axial flow induction factor does not vary radially. In practice, the axial flow induction factor is seldom uniform, but experimental examination of flow through propeller discs by Lock (1924) shows that the assumption of radial independence is acceptable.

      Equating the torque on the elements, given by Eq. (3.47), with the rate of change of angular momentum of the air passing through the swept annulus, given by Eq. (3.34),

      If drag is eliminated from the above two equations, to make a comparison with the results of the vortex theory of Section 3.4, the flow angle ϕ can be determined:

tangent phi equals StartFraction a prime r normal upper Omega Over italic a upper U Subscript infinity Baseline EndFraction equals StartFraction a prime Over a EndFraction StartFraction r Over upper R EndFraction lamda tangent phi equals StartFraction 1 minus a Over lamda Subscript r Baseline left-parenthesis 1 plus a prime right-parenthesis EndFraction

      Equating the two above expressions for tanϕ

StartFraction a prime Over a EndFraction StartFraction r Over upper R EndFraction lamda equals StartFraction 1 minus a Over lamda Subscript r Baseline left-parenthesis 1 plus a prime right-parenthesis EndFraction

      (3.50a)a left-parenthesis 1 minus a right-parenthesis equals lamda Subscript r Baseline Superscript 2 Baseline a prime left-parenthesis 1 plus a prime right-parenthesis

      At the outer edge of the rotor μ = 1 and a = at, so

      (3.50b)a left-parenthesis 1 minus a right-parenthesis equals lamda squared a prime Subscript t Baseline left-parenthesis 1 plus a prime Subscript t right-parenthesis

      where the parameter mu equals StartFraction r Over upper R EndFraction.

      It is convenient to put